0.6*x^2-240*x+7460=0

Solution for 0.6*x^2-240*x+7460=0 equation:

0.6x^2-240x+7460=0

a = 0.6; b = -240; c = +7460;
Δ = b2-4ac
Δ = -2402-4·0.6·7460
Δ = 39696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{39696}=\sqrt{16*2481}=\sqrt{16}*\sqrt{2481}=4\sqrt{2481}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-4\sqrt{2481}}{2*0.6}=\frac{240-4\sqrt{2481}}{1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+4\sqrt{2481}}{2*0.6}=\frac{240+4\sqrt{2481}}{1.2}
$